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Anti-Human NTAN1/PNAd Recombinant Antibody (SAA1874) (HA244013)

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规格:
  • 50ug
  • 100ug
  • 1mg
数量:
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概述
货号HA244013
品牌abinScience
种属反应性Human
应用ELISA
宿主Mouse
克隆类型Monoclonal
同种型IgG2a, kappa
克隆号SAA1874
靶标NTAN1, PNAA, Protein N-terminal asparagine amidohydrolase, Protein NH2-terminal asparagine deamidase, Protein NTN-amidase, Protein N-terminal Asn amidase, Protein N-terminal asparagine amidase, PNAD, Protein NH2-terminal asparagine amidohydrolase
内毒素水平Please contact with the lab for this information.
纯度>95% as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号Q96AB6
RRID

Anti-Human NTAN1/PNAd Antibody (SAA1874) (abinScience Cat# HA244013, RRID:AB_3727637)
_x005F_x000D_

状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:2000-1:20000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze-thaw cycles. Store at 4°C short term (1-2 weeks). Store at -20°C 12 months. Store at -80°C long term.
背景

Protein N-terminal asparagine amidohydrolase (NTAN1/PNAd) is a ~34 kDa protein. N-terminal asparagine deamidase that mediates deamidation of N-terminal asparagine residues to aspartate. Required for the ubiquitin-dependent turnover of intracellular proteins that initiate with Met-Asn. These proteins are acetylated on the retained initiator methionine and can subsequently be modified by the removal of N-acetyl methionine by acylaminoacid hydrolase (AAH). Conversion of the resulting N-terminal asparagine to aspartate by NTAN1/PNAD renders the protein susceptible to arginylation, polyubiquitination and degradation as specified by the N-end rule. This enzyme does not act on substrates with internal or C-terminal asparagines and does not act on glutamine residues in any position, nor on acetylated N-terminal peptidyl Asn.

NoteFor research use only.
图片
  • SDS-PAGE

    SDS-PAGE for Anti-Human NTAN1/PNAd Antibody (SAA1874)

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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