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Anti-Human Human CYP19A1 Recombinant Antibody (SAA2693) (HY384013)

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规格:
  • 50ug
  • 100ug
  • 1mg
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概述
货号HY384013
品牌abinScience
种属反应性Human
应用ELISA
宿主Mouse
克隆类型Monoclonal
同种型IgG2a, kappa
克隆号SAA2693
靶标ARO1, Aromatase, CYAR, CYP19, CYP19A1, CYPXIX, Cytochrome P-450AROM, Cytochrome P450 19A1, EC:1.14.14.14, Estrogen synthase
内毒素水平Please contact with the lab for this information.
纯度>95% as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号P11511
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:2000-1:20000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Aromatase (CYP19A1) is a ~57 kDa protein. A cytochrome P450 monooxygenase that catalyzes the conversion of C19 androgens, androst-4-ene-3,17-dione (androstenedione) and testosterone to the C18 estrogens, estrone and estradiol, respectively. Catalyzes three successive oxidations of C19 androgens: two conventional oxidations at C19 yielding 19-hydroxy and 19-oxo/19-aldehyde derivatives, followed by a third oxidative aromatization step that involves C1-beta hydrogen abstraction combined with cleavage of the C10-C19 bond to yield a phenolic A ring and formic acid. Alternatively, the third oxidative reaction yields a 19-norsteroid and formic acid. Converts dihydrotestosterone to delta1,10-dehydro 19-nordihydrotestosterone and may play a role in homeostasis of this potent androgen. Also displays 2-hydroxylase activity toward estrone.

1. Baravalle, R. et al. (2017) The Journal of steroid biochemistry and molecular biology 167, 23-32. PMID: 27702664
2. Corbin, CJ. et al. (1988) Proceedings of the National Academy of Sciences of the United States of America 85, 8948-52. PMID: 2848247
3. Sohl, CD. et al. (2010) The Journal of biological chemistry 285, 17734-43. PMID: 20385561
4. Cheng, Q. et al. (2012) The Journal of biological chemistry 287, 29554-67. PMID: 22773874
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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