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Anti-ATXN10 Polyclonal Antibody (HV718014)

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规格:
  • 50ug
  • 100ug
数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号HV718014
品牌abinScience
描述
Anti-ATXN10 Polyclonal Antibody (HV718014) is a rabbit polyclonal antibody detecting ATXN10 in ELISA, IHC, WB. Suitable for Human, Bovine, Macaca fascicularis, and Pongo abelii.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human ATXN10 (Leu116-Ala302).
靶标ATXN10, SCA10, Brain protein E46 homolog, Ataxin-10, Spinocerebellar ataxia type 10 protein
纯化方式Purified by antigen affinity column.
Accession号Q9UBB4
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Ataxin-10 (ATXN10) is a ~53 kDa protein. May play a role in the regulation of cytokinesis. May play a role in signaling by stimulating protein glycosylation. Induces neuritogenesis by activating the Ras-MAP kinase pathway and is necessary for the survival of cerebellar neurons. Does not appear to play a major role in ciliogenesis.

1. Li, J. et al. (2011) Cell cycle (Georgetown, Tex.) 10, 2946-58. PMID: 21857149
2. Tian, J. et al. (2015) Scientific reports 5, 8360. PMID: 25666058
NoteFor research use only.
图片
  • Western blot

    Western blot analysis was performed using anti-ATXN10 polyclonal antibody at 1ug/mL on various samples.
    Lane 1: Hela cell lysate
    Lane 2: 293T cell lysate
    Lane 3: HepG2 cell lysate
    Lane 4: Jurkat cell lysate
    Lane 5: SKOV3 cell lysate
    Lane 6: HL-60 cell lysate

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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