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Anti-Human NDOR1 Polyclonal Antibody (HP735014)

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概述
货号HP735014
品牌abinScience
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human NDOR1 (Met1-Leu154).
靶标NR1, NDOR1, NADPH-dependent diflavin oxidoreductase 1, NADPH-dependent FMN and FAD-containing oxidoreductase, Novel reductase 1
纯化方式Purified by antigen affinity column.
Accession号Q9UHB4
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

NADPH-dependent diflavin oxidoreductase 1 (NDOR1) is a ~66 kDa protein. NADPH-dependent reductase which is a central component of the cytosolic iron-sulfur (Fe-S) protein assembly (CIA) machinery. Transfers electrons from NADPH via its FAD and FMN prosthetic groups to the [2Fe-2S] cluster of CIAPIN1, another key component of the CIA machinery. In turn, this reduced cluster provides electrons for assembly of cytosolic iron-sulfur cluster proteins. It can also reduce the [2Fe-2S] cluster of CISD1 and activate this protein implicated in Fe/S cluster repair. In vitro can fully activate methionine synthase/MTR in the presence of soluble cytochrome b5/CYB5A.

1. Paine, MJ. et al. (2000) The Journal of biological chemistry 275, 1471-8. PMID: 10625700
2. Finn, RD. et al. (2005) Pharmacogenetics and genomics 15, 381-6. PMID: 15900210
3. Netz, DJ. et al. (2010) Nature chemical biology 6, 758-65. PMID: 20802492
4. Banci, L. et al. (2013) Proceedings of the National Academy of Sciences of the United States of America 110, 7136-41. PMID: 23596212
5. Camponeschi, F. et al. (2017) Journal of the American Chemical Society 139, 9479-9482. PMID: 28648056
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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