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Anti-Human TLR5 Polyclonal Antibody (HT266014)

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概述
货号HT266014
品牌abinScience
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human TLR5 (Ile21-Phe115).
靶标TIL3, TLR5, Toll/interleukin-1 receptor-like protein 3, Toll-like receptor 5
纯化方式Purified by antigen affinity column.
Accession号O60602
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Toll-like receptor 5 (CD285/TLR5) is a ~97 kDa protein. Pattern recognition receptor (PRR) located on the cell surface that participates in the activation of innate immunity and inflammatory response. Recognizes small molecular motifs named pathogen-associated molecular pattern (PAMPs) expressed by pathogens and microbe-associated molecular patterns (MAMPs) usually expressed by resident microbiota. Upon ligand binding such as bacterial flagellins, recruits intracellular adapter proteins MYD88 and TRIF leading to NF-kappa-B activation, cytokine secretion and induction of the inflammatory response. Plays thereby an important role in the relationship between the intestinal epithelium and enteric microbes and contributes to the gut microbiota composition throughout life.

1. Hayashi, F. et al. (2001) Nature 410, 1099-103. PMID: 11323673
2. Blohmke, CJ. et al. (2008) Journal of immunology (Baltimore, Md. : 1950) 180, 7764-73. PMID: 18490781
3. Bielaszewska, M. et al. (2018) International journal of medical microbiology : IJMM 308, 882-889. PMID: 29934223
4. Gewirtz, AT. et al. (2001) Journal of immunology (Baltimore, Md. : 1950) 167, 1882-5. PMID: 11489966
5. Choi, YJ. et al. (2010) The Journal of biological chemistry 285, 37570-8. PMID: 20855887
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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