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Anti-ABCC3 Polyclonal Antibody (HT036014)

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规格:
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  • 100ug
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概述
货号HT036014
品牌abinScience
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human ABCC3 (Phe1291-Asp1523).
靶标ABCC3, MRP3, MOAT-D, CMOAT2, Canalicular multispecific organic anion transporter 2, ATP-binding cassette sub-family C member 3, Multidrug resistance-associated protein 3, Multi-specific organic anion transporter D, MLP2
纯化方式Purified by antigen affinity column.
Accession号O15438
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

ATP-binding cassette sub-family C member 3 (ABCC3/MRP3) is a ~169 kDa protein. ATP-dependent transporter of the ATP-binding cassette (ABC) family that binds and hydrolyzes ATP to enable active transport of various substrates including many drugs, toxicants and endogenous compound across cell membranes. Transports glucuronide conjugates such as bilirubin diglucuronide, estradiol-17-beta-o-glucuronide and GSH conjugates such as leukotriene C4 (LTC4). Transports also various bile salts (taurocholate, glycocholate, taurochenodeoxycholate-3-sulfate, taurolithocholate- 3-sulfate). Does not contribute substantially to bile salt physiology but provides an alternative route for the export of bile acids and glucuronides from cholestatic hepatocytes. May contribute to regulate the transport of organic compounds in testes across the blood-testis-barrier (Probable).

1. Kool, M. et al. (1999) Proceedings of the National Academy of Sciences of the United States of America 96, 6914-9. PMID: 10359813
2. Zelcer, N. et al. (2001) The Journal of biological chemistry 276, 46400-7. PMID: 11581266
3. Lee, YM. et al. (2004) Pharmacogenetics 14, 213-23. PMID: 15083066
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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