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Anti-Human FSTL1 Recombinant Antibody (SAA1665) (HC289013)

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规格:
  • 50ug
  • 100ug
  • 1mg
数量:
  • 概述

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  • 参考文献

  • 产品说明书

概述
货号HC289013
品牌abinScience
种属反应性Human
应用ELISA
宿主Mouse
克隆类型Monoclonal
同种型IgG2a, kappa
克隆号SAA1665
靶标FSTL1, Follistatin-related protein 1, Follistatin-like protein 1, FRP
内毒素水平Please contact with the lab for this information.
纯度>95% as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号Q12841
RRIDAnti-Human FSTL1 Antibody (SAA1665) (abinScience Cat# HC289013, RRID:AB_3727426)
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:2000-1:20000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze-thaw cycles. Store at 4°C short term (1-2 weeks). Store at -20°C 12 months. Store at -80°C long term.
背景

Follistatin-related protein 1 (FSTL1) is a ~34 kDa protein. Secreted glycoprotein that is involved in various physiological processes, such as angiogenesis, regulation of the immune response, cell proliferation and differentiation. Plays a role in the development of the central nervous system, skeletal system, lungs, and ureter. Promotes endothelial cell survival, migration and differentiation into network structures in an AKT-dependent manner. Also promotes survival of cardiac myocytes. Initiates various signaling cascades by activating different receptors on the cell surface such as DIP2A, TLR4 or BMP receptors.

1. Murakami, K. et al. (2012) FEBS letters 586, 319-24. PMID: 22265692
2. Jin, X. et al. (2017) Cellular physiology and biochemistry : international journal of experimental cellular physiology, biochemistry, and pharmacology 44, 1616-1628. PMID: 29212066
3. Ouchi, N. et al. (2010) The Journal of biological chemistry 285, 7127-34. PMID: 20054002
NoteFor research use only.
图片
  • SDS-PAGE

    SDS-PAGE for Anti-Human FSTL1 Antibody (SAA1665)

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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