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Anti-NR4A2 Polyclonal Antibody (PTX20403)

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概述
货号PTX20403
品牌ProteoGenix
描述
Anti-NR4A2 Polyclonal Antibody (PTX20403) is a rabbit polyclonal antibody detecting Transcriptionally-inducible nuclear receptor, NURR1, NR4A2, NOT, Nuclear receptor subfamily 4 group A member 2, Orphan nuclear receptor NURR1, TINUR, Immediate-early response protein NOT in ELISA, IHC, WB. Suitable for Human, Mouse, Rat.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human NR4A2 (Met1-Thr335).
靶标Transcriptionally-inducible nuclear receptor, NURR1, NR4A2, NOT, Nuclear receptor subfamily 4 group A member 2, Orphan nuclear receptor NURR1, TINUR, Immediate-early response protein NOT
纯化方式Purified by antigen affinity column.
Accession号P43354
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Nuclear receptor subfamily 4 group A member 2 (NR4A2) is a ~66 kDa protein. Transcriptional regulator which is important for the differentiation and maintenance of meso-diencephalic dopaminergic (mdDA) neurons during development. It is crucial for expression of a set of genes such as SLC6A3, SLC18A2, TH and DRD2 which are essential for development of mdDA neurons.

1. Flaig, R. et al. (2005) The Journal of biological chemistry 280, 19250-8. PMID: 15716272
2. Messmer, K. et al. (2007) International journal of developmental neuroscience : the official journal of the International Society for Developmental Neuroscience 25, 29-37. PMID: 17184956
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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