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Anti-SLC6A5 Polyclonal Antibody (HA595014)

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概述
货号HA595014
品牌abinScience
描述
Anti-SLC6A5 Polyclonal Antibody (HA595014) is a rabbit polyclonal antibody detecting Sodium- and chloride-dependent glycine transporter 2; GlyT-2; GlyT2; Solute carrier family 6 member 5; SLC6A5; GLYT2; NET1 in ELISA, IHC, WB. Suitable for Human, Rat, and Mouse.
Highlights
  • ●Affinity Purified — Minimal background and high purity for reliable results.
  • ●Multi-Application — Validated across multiple applications.
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant human SLC6A5 (Cys292-Arg393).
靶标Sodium- and chloride-dependent glycine transporter 2; GlyT-2; GlyT2; Solute carrier family 6 member 5; SLC6A5; GLYT2; NET1
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q9Y345, P58295, Q761V0
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Sodium- and chloride-dependent glycine transporter 2 (SLC6A5) is a ~87 kDa protein. Sodium- and chloride-dependent glycine transporter. Terminates the action of glycine by its high affinity sodium-dependent reuptake into presynaptic terminals. May be responsible for the termination of neurotransmission at strychnine-sensitive glycinergic synapses.

1. Gallagher, MJ. et al. (1999) Brain research. Molecular brain research 70, 101-15. PMID: 10381548
2. Evans, J. et al. (1999) FEBS letters 463, 301-6. PMID: 10606742
3. Rees, MI. et al. (2006) Nature genetics 38, 801-6. PMID: 16751771
4. Kitzenmaier, A. et al. (2019) The European journal of neuroscience 50, 3906-3920. PMID: 31370103
5. Morrow, JA. et al. (1998) FEBS letters 439, 334-40. PMID: 9845349
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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