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Anti-RNF220 Polyclonal Antibody (HA773014)

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概述
货号HA773014
品牌abinScience
描述
Anti-RNF220 Polyclonal Antibody (HA773014) is a rabbit polyclonal antibody detecting E3 ubiquitin-protein ligase RNF220; 2.3.2.27; RING finger protein 220; RING-type E3 ubiquitin transferase RNF220; RNF220; C1orf164 in ELISA, IHC, WB. Suitable for Human, Bovine, and Mouse.
Highlights
  • ●Affinity Purified — Minimal background and high purity for reliable results.
  • ●Multi-Application — Validated across multiple applications.
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant human RNF220 (Lys482-Leu566).
靶标E3 ubiquitin-protein ligase RNF220; 2.3.2.27; RING finger protein 220; RING-type E3 ubiquitin transferase RNF220; RNF220; C1orf164
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q5VTB9, Q08DV5, Q6PDX6
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

E3 ubiquitin-protein ligase RNF220 is a ~62 kDa protein. E3 ubiquitin-protein ligase that promotes the ubiquitination and proteasomal degradation of SIN3B. Independently of its E3 ligase activity, acts as a CTNNB1 stabilizer through USP7-mediated deubiquitination of CTNNB1 promoting Wnt signaling. Plays a critical role in the regulation of nuclear lamina.

1. Ma, P. et al. (2014) Molecular and cellular biology 34, 4355-66. PMID: 25266658
2. Sferra, A. et al. (2021) Brain : a journal of neurology 144, 3020-3035. PMID: 33964137
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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