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Anti-CDK2AP2 Polyclonal Antibody (HB451014)

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概述
货号HB451014
品牌abinScience
描述
Anti-CDK2AP2 Polyclonal Antibody (HB451014) is a rabbit polyclonal antibody detecting Cyclin-dependent kinase 2-associated protein 2; CDK2-associated protein 2; DOC-1-related protein; DOC-1R; CDK2AP2; DOC1R in ELISA, IHC, WB. Suitable for Human, Bovine, and Mouse.
Highlights
  • ●Affinity Purified — Minimal background and high purity for reliable results.
  • ●Multi-Application — Validated across multiple applications.
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant human CDK2AP2 (Asn49-Thr126).
靶标Cyclin-dependent kinase 2-associated protein 2; CDK2-associated protein 2; DOC-1-related protein; DOC-1R; CDK2AP2; DOC1R
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号O75956, Q58CN7, Q9CPY4
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Cyclin-dependent kinase 2-associated protein 2 (CDK2AP2) is a ~13 kDa protein. Acts as a component of the histone deacetylase NuRD complex which participates in the remodeling of chromatin. Inhibits cell cycle G1/S phase transition by repressing CDK2 expression and activation; represses CDK2 activation by inhibiting its interaction with cyclin E and A. Plays a role in regulating the self-renewal of embryonic stem cells (ESCs) and in maintaining cell survival during terminal differentiation of ESCs. Regulates microtubule organization of metaphase II oocytes.

1. Spruijt, CG. et al. (2021) The FEBS journal 288, 3231-3245. PMID: 33283408
2. Liu, Q. et al. (2013) International journal of biological sciences 9, 541-9. PMID: 23781148
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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