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Anti-IRX4 Polyclonal Antibody (HB510014)

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概述
货号HB510014
品牌abinScience
描述
Anti-IRX4 Polyclonal Antibody (HB510014) is a rabbit polyclonal antibody detecting Iroquois-class homeodomain protein IRX-4; Homeodomain protein IRXA3; Iroquois homeobox protein 4; IRX4; IRXA3 in ELISA, IHC, WB. Suitable for Chicken, Human, Frog, Mouse, and Zebrafish.
Highlights
  • ●Affinity Purified — Minimal background and high purity for reliable results.
  • ●Multi-Application — Validated across multiple applications.
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant human IRX4 (Asn148-Met206).
靶标Iroquois-class homeodomain protein IRX-4; Homeodomain protein IRXA3; Iroquois homeobox protein 4; IRX4; IRXA3
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q9YGS0, P78413, Q90XW6, B7ZRT8, Q9QY61, P78412, P78415, P81067, Q503Z8, O42261, P81068, Q9ER75, P78414, Q6DCQ1, Q2TAQ8, Q9BZI1, Q1LXU5, Q9JKQ4, P78411, Q9YGK8, P54269, Q24248, P81066, Q90XW5
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Iroquois-class homeodomain protein IRX-4 (IRX4) is a ~52 kDa protein. Regulates the chamber-specific expression of myosin isoforms by activating the expression of the ventricle myosin heavy chain-1 (Vmhc1) and suppressing the expression of the atrial myosin heavy chain-1 (Amhc1) in the ventricles. May play a critical role in establishing chamber-specific gene expression in the developing heart.

NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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