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Anti-Human CD191/CCR1 Recombinant Antibody (SAA2405) (HB896013)

价格:
规格:
  • 50ug
  • 100ug
  • 1mg
数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号HB896013
品牌abinScience
种属反应性Human
应用ELISA, FCM, Neutralization
同种型IgG2a, kappa
克隆号SAA2405
靶标C-C chemokine receptor type 1, C-C CKR-1, CC-CKR-1, CCR-1, CCR1, HM145, LD78 receptor, Macrophage inflammatory protein 1-alpha receptor, MIP-1alpha-R, RANTES-R, CD191, CCR1, CMKBR1, CMKR1, SCYAR1
内毒素水平<10 EU/mg
纯度>95% as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号P32246
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:2000-1:20000
背景

C-C chemokine receptor type 1 (CD191/CCR1) is a ~41 kDa protein. Chemokine receptor that plays a crucial role in regulating immune cell migration, inflammation, and immune responses. Contributes to the inflammatory response by recruiting immune cells, such as monocytes, macrophages, T-cells, and dendritic cells, to sites of inflammation for the clearance of pathogens and the resolution of tissue damage. When activated by its ligands including CCL3, CCL5-9, CCL13-16 and CCL23, triggers a signaling cascade within immune cells, leading to their migration towards the source of the chemokine. For example, mediates neutrophil migration after activation by CCL3 leading to the sequential release of TNF and leukotriene B4. Also mediates monocyte migration upon CXCL4 binding.

1. Tian, Y. et al. (2004) European journal of immunology 34, 785-795. PMID: 14991608
2. Berahovich, RD. et al. (2005) Journal of immunology (Baltimore, Md. : 1950) 174, 7341-51. PMID: 15905581
3. Wei, H. et al. (2024) Cellular signalling 117, 111122. PMID: 38417634
4. Fox, JM. et al. (2018) Scientific reports 8, 9466. PMID: 29930254
NoteFor research use only
图片
  • SDS-PAGE

    SDS-PAGE for Anti-Human CD191/CCR1 Antibody (SAA2405)

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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