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Anti-Human CIAPIN1 Polyclonal Antibody (ARO-A12188)

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概述
货号ARO-A12188
品牌ProteoGenix
描述
Anti-Human CIAPIN1 Polyclonal Antibody (ARO-A12188) is a rabbit polyclonal antibody detecting Cytokine-induced apoptosis inhibitor 1, Anamorsin, Fe-S cluster assembly protein DRE2 homolog, CIAPIN1 in ELISA, IHC, WB. Suitable for Human.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human CIAPIN1 (Met1-Lys163).
靶标Cytokine-induced apoptosis inhibitor 1, Anamorsin, Fe-S cluster assembly protein DRE2 homolog, CIAPIN1
纯化方式Purified by antigen affinity column.
Accession号Q6FI81
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Anamorsin (CIAPIN1) is a ~33 kDa protein. Component of the cytosolic iron-sulfur (Fe-S) protein assembly (CIA) machinery required for the maturation of extramitochondrial Fe-S proteins. Part of an electron transfer chain functioning in an early step of cytosolic Fe-S biogenesis, facilitating the de novo assembly of a [4Fe-4S] cluster on the scaffold complex NUBP1-NUBP2. Electrons are transferred to CIAPIN1 from NADPH via the FAD- and FMN-containing protein NDOR1. NDOR1-CIAPIN1 are also required for the assembly of the diferric tyrosyl radical cofactor of ribonucleotide reductase (RNR), probably by providing electrons for reduction during radical cofactor maturation in the catalytic small subunit. Has anti-apoptotic effects in the cell.

1. Banci, L. et al. (2013) Proceedings of the National Academy of Sciences of the United States of America 110, 7136-41. PMID: 23596212
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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