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Anti-Human RAB18 Polyclonal Antibody (ARO-A12427)

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概述
货号ARO-A12427
品牌ProteoGenix
描述
Anti-Human RAB18 Polyclonal Antibody (ARO-A12427) is a rabbit polyclonal antibody detecting Ras-related protein Rab-18, RAB18 in ELISA, IHC, WB. Suitable for Human, Mouse, Rat, Bos taurus, Danio rerio, Chicken, Pongo abelii.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat, Bos taurus, Danio rerio, Chicken, Pongo abelii
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human RAB18 (Met1-Lys183).
靶标Ras-related protein Rab-18, RAB18
纯化方式Purified by antigen affinity column.
Accession号Q9NP72
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Ras-related protein Rab-18 (RAB18) is a ~22 kDa protein. The small GTPases Rab are key regulators of intracellular membrane trafficking, from the formation of transport vesicles to their fusion with membranes. Rabs cycle between an inactive GDP-bound form and an active GTP-bound form that is able to recruit to membranes different sets of downstream effectors directly responsible for vesicle formation, movement, tethering and fusion. RAB18 is required for the localization of ZFYVE1 to lipid droplets and for its function in mediating the formation of endoplasmic reticulum-lipid droplets (ER-LD) contacts. Also required for maintaining endoplasmic reticulum structure. Plays a role in apical endocytosis/recycling.

1. Gerondopoulos, A. et al. (2014) The Journal of cell biology 205, 707-20. PMID: 24891604
2. Li, D. et al. (2019) Cell reports 27, 343-358.e5. PMID: 30970241
3. Bem, D. et al. (2011) American journal of human genetics 88, 499-507. PMID: 21473985
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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