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Anti-Human CAVIN1 Polyclonal Antibody (ARO-A12585)

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概述
货号ARO-A12585
品牌ProteoGenix
描述
Anti-Human CAVIN1 Polyclonal Antibody (ARO-A12585) is a rabbit polyclonal antibody detecting Polymerase I and transcript release factor, CAVIN1, Caveolae-associated protein 1, Cavin-1, PTRF in ELISA, IHC, WB. Suitable for Human, Mouse, Rat.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human CAVIN1 (Leu43-Val153).
靶标Polymerase I and transcript release factor, CAVIN1, Caveolae-associated protein 1, Cavin-1, PTRF
纯化方式Purified by antigen affinity column.
Accession号Q6NZI2
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Caveolae-associated protein 1 (CAVIN1) is a ~43 kDa protein. Plays an important role in caveolae formation and organization. Essential for the formation of caveolae in all tissues. Core component of the CAVIN complex which is essential for recruitment of the complex to the caveolae in presence of calveolin-1 (CAV1). Essential for normal oligomerization of CAV1. Promotes ribosomal transcriptional activity in response to metabolic challenges in the adipocytes and plays an important role in the formation of the ribosomal transcriptional loop.

1. Liu, L. et al. (2008) The Journal of biological chemistry 283, 4314-22. PMID: 18056712
2. Hill, MM. et al. (2008) Cell 132, 113-24. PMID: 18191225
3. Hayashi, YK. et al. (2009) The Journal of clinical investigation 119, 2623-33. PMID: 19726876
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量，自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项，自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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