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Anti-Human NDE1 Polyclonal Antibody (ARO-A12607)

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概述
货号ARO-A12607
品牌ProteoGenix
描述
Anti-Human NDE1 Polyclonal Antibody (ARO-A12607) is a rabbit polyclonal antibody detecting NudE, Nuclear distribution protein nudE homolog 1, NUDE, NDE1 in ELISA, IHC, WB. Suitable for Human, Mouse, Rat, Chicken.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat, Chicken
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human NDE1 (Phe8-Glu187).
靶标NudE, Nuclear distribution protein nudE homolog 1, NUDE, NDE1
纯化方式Purified by antigen affinity column.
Accession号Q9NXR1
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Nuclear distribution protein nudE homolog 1 (NDE1) is a ~37 kDa protein. Required for centrosome duplication and formation and function of the mitotic spindle. Essential for the development of the cerebral cortex. May regulate the production of neurons by controlling the orientation of the mitotic spindle during division of cortical neuronal progenitors of the proliferative ventricular zone of the brain. Orientation of the division plane perpendicular to the layers of the cortex gives rise to two proliferative neuronal progenitors whereas parallel orientation of the division plane yields one proliferative neuronal progenitor and a postmitotic neuron. A premature shift towards a neuronal fate within the progenitor population may result in an overall reduction in the final number of neurons and an increase in the number of neurons in the deeper layers of the cortex.

1. Zhang, Y. et al. (2022) Structure (London, England : 1993) 30, 386-395.e5. PMID: 34793709
NoteFor research use only.
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参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量，自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项，自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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