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Anti-AOC1/DAO Polyclonal Antibody (ARO-A14077)

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概述
货号ARO-A14077
品牌ProteoGenix
描述
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human AOC1/DAO (Glu20-Trp322).
靶标AOC1, ABP1, DAO, Kidney amine oxidase, Histaminase, Amiloride-sensitive amine oxidase [copper-containing], Amiloride-binding protein 1, Diamine oxidase, KAO, DAO1, Amine oxidase copper domain-containing protein 1
纯化方式Purified by antigen affinity column.
Accession号P19801
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Diamine oxidase [copper-containing] (AOC1/DAO) is a ~85 kDa protein. Catalyzes the oxidative deamination of primary amines to the corresponding aldehydes with the concomitant production of hydrogen peroxide and ammonia. Its preferred substrates are the diamines histamine and 1-methylhistamine and it could therefore play a role in allergic and immune responses. Has a broad specificity for diamines and can also act on cadaverine and putrescine, two products of amino acid catabolism. It could also act on polyamines, like spermidine and spermine though less efficiently, and regulate various biological processes.

1. Elmore, BO. et al. (2002) Journal of biological inorganic chemistry : JBIC : a publication of the Society of Biological Inorganic Chemistry 7, 565-79. PMID: 12072962
2. McGrath, AP. et al. (2009) Biochemistry 48, 9810-22. PMID: 19764817
3. Hölttä, E. et al. (1975) The Biochemical journal 145, 373-8. PMID: 239684
4. Novotny, WF. et al. (1994) The Journal of biological chemistry 269, 9921-5. PMID: 8144586
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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