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Anti-PDHB Polyclonal Antibody (ARO-A14144)

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概述
货号ARO-A14144
品牌ProteoGenix
描述
Anti-PDHB Polyclonal Antibody (ARO-A14144) is a rabbit polyclonal antibody detecting PDHB, PDHE1-B, PHE1B, Pyruvate dehydrogenase E1 component subunit beta, mitochondrial in ELISA, IHC, WB. Suitable for Human, Mouse, Rat, Bos taurus, Pongo abelii.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat, Bos taurus, Pongo abelii
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human PDHB (Leu31-Asn341).
靶标PDHB, PDHE1-B, PHE1B, Pyruvate dehydrogenase E1 component subunit beta, mitochondrial
纯化方式Purified by antigen affinity column.
Accession号P11177
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Pyruvate dehydrogenase E1 component subunit beta, mitochondrial (PDHB) is a ~39 kDa protein. Together with PDHA1 forms the heterotetrameric E1 subunit of the pyruvate dehydrogenase (PDH) complex. The PDH complex catalyzes the overall conversion of pyruvate to acetyl-CoA and CO(2), and thereby links cytoplasmic glycolysis and the mitochondrial tricarboxylic acid (TCA) cycle (Probable). It contains multiple copies of three enzymatic components: pyruvate dehydrogenase (E1), dihydrolipoamide acetyltransferase (E2) and dihydrolipoamide dehydrogenase (E3) (Probable). The E1 subunit catalyzes both the thiamine pyrophosphate (TPP)-dependent decarboxylation of pyruvate and the reductive acetylation of a lipoyl group covalently linked to the lipoyl-bearing domains of E2.

1. Seifert, F. et al. (2007) Biochemistry 46, 6277-87. PMID: 17474719
2. Kato, M. et al. (2008) Structure (London, England : 1993) 16, 1849-59. PMID: 19081061
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量，自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项，自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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