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Anti-Human FMO5 Polyclonal Antibody (HD536014)

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概述
货号HD536014
品牌abinScience
描述
Anti-Human FMO5 Polyclonal Antibody (HD536014) is a rabbit polyclonal antibody detecting FMO5. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human FMO5 (Met1-Ser512).
靶标Baeyer-Villiger monooxygenase 1, Dimethylaniline monooxygenase [N-oxide-forming] 5, Dimethylaniline oxidase 5, EC:1.14.13.-, EC:1.14.13.8, EC:1.6.3.1, FMO 5, FMO5, Flavin-containing monooxygenase 5, NADPH oxidase, hBVMO1
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号P49326
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Flavin-containing monooxygenase 5 (FMO5) is a ~60 kDa protein. Acts as a Baeyer-Villiger monooxygenase on a broad range of substrates. Catalyzes the insertion of an oxygen atom into a carbon-carbon bond adjacent to a carbonyl, which converts ketones to esters. Active on diverse carbonyl compounds, whereas soft nucleophiles are mostly non- or poorly reactive. In contrast with other forms of FMO it is non- or poorly active on 'classical' substrates such as drugs, pesticides, and dietary components containing soft nucleophilic heteroatoms (Probable). Able to oxidize drug molecules bearing a carbonyl group on an aliphatic chain, such as nabumetone and pentoxifylline.

1. Lai, WG. et al. (2011) Drug metabolism and disposition: the biological fate of chemicals 39, 61-70. PMID: 20947616
2. Fiorentini, F. et al. (2016) ACS chemical biology 11, 1039-48. PMID: 26771671
3. Fiorentini, F. et al. (2017) ACS chemical biology 12, 2379-2387. PMID: 28783300
4. Overby, LH. et al. (1995) Archives of biochemistry and biophysics 317, 275-84. PMID: 7872795
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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