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Anti-Human HDAC7 Polyclonal Antibody (HV082014)

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概述
货号HV082014
品牌abinScience
描述
Anti-Human HDAC7 Polyclonal Antibody (HV082014) is a rabbit polyclonal antibody detecting HDAC7. Suitable for Mouse and Human.
Highlights
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human HDAC7 (Ser482-Ser903).
靶标EC:3.5.1.-, EC:3.5.1.98, HD7, HD7a, HDAC7, HDAC7A, Histone deacetylase 7, Histone deacetylase 7A, Protein deacetylase HDAC7
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q8WUI4
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Histone deacetylase 7 (HDAC7) is a ~102 kDa protein. Responsible for the deacetylation of lysine residues on the N-terminal part of the core histones (H2A, H2B, H3 and H4). Histone deacetylation gives a tag for epigenetic repression and plays an important role in transcriptional regulation, cell cycle progression and developmental events. Histone deacetylases act via the formation of large multiprotein complexes. Involved in muscle maturation by repressing transcription of myocyte enhancer factors such as MEF2A, MEF2B and MEF2C. During muscle differentiation, it shuttles into the cytoplasm, allowing the expression of myocyte enhancer factors.

1. Bryant, H. et al. (2002) Journal of virology 76, 10290-8. PMID: 12239305
2. Li, B. et al. (2007) Proceedings of the National Academy of Sciences of the United States of America 104, 4571-6. PMID: 17360565
3. Lee, DY. et al. (2017) Proceedings of the National Academy of Sciences of the United States of America 114, 2072-2077. PMID: 28167758
4. Zhang, XL. et al. (2023) Nature communications 14, 3815. PMID: 37369679
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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