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Anti-Human CIP2A Polyclonal Antibody (HV712014)

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概述
货号HV712014
品牌abinScience
描述
Anti-Human CIP2A Polyclonal Antibody (HV712014) is a rabbit polyclonal antibody detecting Protein CIP2A. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human CIP2A (Asp2-Glu560).
靶标CIP2A, Cancerous inhibitor of PP2A, KIAA1524, Protein CIP2A, p90 autoantigen
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q8TCG1
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Protein CIP2A is a ~102 kDa protein. Acts as an inhibitor of protein phosphatase PP2A. Promotes anchorage-independent cell growth and tumor formation by preventing dephosphorylation of MYC, thereby stabilizing MYC in human malignancies. Together with TOPBP1, plays an essential role in the response to genome instability generated by the presence of acentric chromosome fragments derived from shattered chromosomes within micronuclei. Micronuclei, which are frequently found in cancer cells, consist of chromatin surrounded by their own nuclear membrane: following breakdown of the micronuclear envelope, a process associated with chromothripsis, the CIP2A-TOPBP1 complex tethers chromosome fragments during mitosis to ensure clustered segregation of the fragments to a single daughter cell nucleus, facilitating re-ligation with limited chromosome scattering and loss.

1. Junttila, MR. et al. (2007) Cell 130, 51-62. PMID: 17632056
2. Adam, S. et al. (2021) Nature cancer 2, 1357-1371. PMID: 35121901
3. De Marco Zompit, M. et al. (2022) Nature communications 13, 4143. PMID: 35842428
4. Lin, YF. et al. (2023) Nature 618, 1041-1048. PMID: 37165191
5. Trivedi, P. et al. (2023) Nature 618, 1049-1056. PMID: 37316668
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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