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Anti-Human FKTN Polyclonal Antibody (HD574014)

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概述
货号HD574014
品牌abinScience
描述
Anti-Human FKTN Polyclonal Antibody (HD574014) is a rabbit polyclonal antibody detecting FKTN. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human FKTN (Cys250-Tyr461).
靶标EC:2.7.8.-, FCMD, FKTN, Fukutin, Fukuyama-type congenital muscular dystrophy protein, Ribitol-5-phosphate transferase, Ribitol-5-phosphate transferase FKTN
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号O75072
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Ribitol-5-phosphate transferase FKTN is a ~53 kDa protein. Catalyzes the transfer of a ribitol-phosphate from CDP-ribitol to the distal N-acetylgalactosamine of the phosphorylated O-mannosyl trisaccharide (N-acetylgalactosamine-beta-3-N-acetylglucosamine-beta-4-(phosphate-6-)mannose), a carbohydrate structure present in alpha-dystroglycan (DAG1). This constitutes the first step in the formation of the ribitol 5-phosphate tandem repeat which links the phosphorylated O-mannosyl trisaccharide to the ligand binding moiety composed of repeats of 3-xylosyl-alpha-1,3-glucuronic acid-beta-1. Required for normal location of POMGNT1 in Golgi membranes, and for normal POMGNT1 activity. May interact with and reinforce a large complex encompassing the outside and inside of muscle membranes. Could be involved in brain development (Probable).

1. Kanagawa, M. et al. (2016) Cell reports 14, 2209-2223. PMID: 26923585
2. Gerin, I. et al. (2016) Nature communications 7, 11534. PMID: 27194101
3. Nishihara, R. et al. (2018) Biochemical and biophysical research communications 497, 1025-1030. PMID: 29477842
4. Xiong, H. et al. (2006) Biochemical and biophysical research communications 350, 935-41. PMID: 17034757
5. Willer, T. et al. (2014) eLife 3. PMID: 25279699
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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