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Anti-Human FIG4 Polyclonal Antibody (HP232014)

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规格:
  • 50ug
  • 100ug
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概述
货号HP232014
品牌abinScience
描述
Anti-Human FIG4 Polyclonal Antibody (HP232014) is a rabbit polyclonal antibody detecting FIG4. Suitable for Human and Mouse.
Highlights
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human FIG4 (Gly216-His665).
靶标EC:3.1.3.-, EC:3.1.3.16, EC:3.1.3.36, EC:3.1.3.86, FIG4, KIAA0274, Phosphatidylinositol 3,5-bisphosphate 5-phosphatase, Polyphosphoinositide phosphatase, SAC domain-containing protein 3, SAC3, Serine-protein phosphatase FIG4
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q92562
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Polyphosphoinositide phosphatase (FIG4) is a ~103 kDa protein. Dual specificity phosphatase component of the PI(3,5)P2 regulatory complex which regulates both the synthesis and turnover of phosphatidylinositol 3,5-bisphosphate (PtdIns(3,5)P2). Catalyzes the dephosphorylation of phosphatidylinositol 3,5-bisphosphate (PtdIns(3,5)P2) to form phosphatidylinositol 3-phosphate. Has serine-protein phosphatase activity acting on PIKfyve to stimulate its lipid kinase activity, its catalytically activity being required for maximal PI(3,5)P2 production. In vitro, hydrolyzes all three D5-phosphorylated polyphosphoinositide and although displaying preferences for PtdIns(3,5)P2, it is capable of hydrolyzing PtdIns(3,4,5)P3 and PtdIns(4,5)P2, at least in vitro.

1. Sbrissa, D. et al. (2007) The Journal of biological chemistry 282, 23878-91. PMID: 17556371
2. Lees, JA. et al. (2020) Molecular cell 80, 736-743.e4. PMID: 33098764
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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