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Anti-Mouse IL-13 Polyclonal Antibody (MW632014)

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概述
货号MW632014
品牌abinScience
描述
Anti-Mouse IL13 Polyclonal Antibody (MW632014) is a rabbit polyclonal antibody detecting Il13. Suitable for Mouse.
种属反应性Mouse
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Mouse IL13 (Ser26-Phe131).
靶标IL-13, Il-13, Il13, Interleukin-13, T-cell activation protein P600
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号P20109
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Interleukin-13 (IL13) is a ~14 kDa protein. Cytokine that plays important roles in allergic inflammation and immune response to parasite infection. Synergizes with IL2 in regulating interferon-gamma synthesis. Stimulates B-cell proliferation, and activation of eosinophils, basophils, and mast cells. Plays an important role in controlling IL33 activity by modulating the production of transmembrane and soluble forms of interleukin-1 receptor-like 1/IL1RL1. Displays the capacity to antagonize Th1-driven proinflammatory immune response and downregulates synthesis of many proinflammatory cytokines including IL1, IL6, IL10, IL12 and TNF through a mechanism that partially involves suppression of NF-kappa-B.

1. Finkelman, FD. et al. (2004) Immunological reviews 201, 139-55. PMID: 15361238
2. Zhang, M. et al. (2021) Journal of immunology (Baltimore, Md. : 1950) 207, 3070-3080. PMID: 34789557
3. Mayer, JU. et al. (2021) Nature immunology 22, 1538-1550. PMID: 34795444
4. Takeda, K. et al. (1996) Journal of immunology (Baltimore, Md. : 1950) 157, 3220-2. PMID: 8871614
5. Duffen, J. et al. (2018) Journal of immunology (Baltimore, Md. : 1950) 200, 1347-1359. PMID: 29305434
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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