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Anti-Human CBX4 Polyclonal Antibody (HT334014)

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概述
货号HT334014
品牌abinScience
描述
Anti-Human CBX4 Polyclonal Antibody (HT334014) is a rabbit polyclonal antibody detecting CBX4. Suitable for Human.
种属反应性Human, Mouse
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human CBX4 (Glu2-Gly73&Gly245-Gln275).
靶标CBX4, Chromobox protein homolog 4, E3 SUMO-protein ligase CBX4, EC:2.3.2.-, Pc2, Polycomb 2 homolog, hPc2
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号O00257
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

E3 SUMO-protein ligase CBX4 is a ~61 kDa protein. E3 SUMO-protein ligase that catalyzes sumoylation of target proteins by promoting the transfer of SUMO from the E2 enzyme to the substrate. Also acts as a histone reader, which specifically recognizes and binds histone H3 trimethylated at 'Lys-9' and 'Lys-27' (H3K9me3 and H3K27me3, respectively) via its chromo domain. Catalyzes sumoylation of HNRNPK, a p53/TP53 transcriptional coactivator, hence indirectly regulates p53/TP53 transcriptional activation resulting in p21/CDKN1A expression. Acts as a regulator of brown adipocyte differentiation by mediating sumoylation of PRDM16, thereby preventing PRDM16 ubiquitination and degradation. Monosumoylates ZNF131.

1. Kagey, MH. et al. (2003) Cell 113, 127-37. PMID: 12679040
2. Oh, Y. et al. (2012) The Journal of biological chemistry 287, 17517-17529. PMID: 22467880
3. Pelisch, F. et al. (2012) The Journal of biological chemistry 287, 30789-99. PMID: 22825850
4. Levine, SS. et al. (2002) Molecular and cellular biology 22, 6070-8. PMID: 12167701
5. Maertens, GN. et al. (2009) PloS one 4, e6380. PMID: 19636380
6. Vandamme, J. et al. (2011) Molecular & cellular proteomics : MCP 10, M110.002642. PMID: 21282530
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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