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Anti-Human TRIM65 Polyclonal Antibody (HD347014)

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概述
货号HD347014
品牌abinScience
描述
Anti-Human TRIM65 Polyclonal Antibody (HD347014) is a rabbit polyclonal antibody detecting TRIM65. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human TRIM65 (Val319-Ser517).
靶标E3 ubiquitin-protein ligase TRIM65, EC:2.3.2.27, TRIM65, Tripartite motif-containing protein 65
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q6PJ69
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

E3 ubiquitin-protein ligase TRIM65 is a ~57 kDa protein. E3 ubiquitin ligase that plays a role in several processes including innate immnity, autophagy or inflammation. Negatively regulates miRNAs by modulating the ubiquitination and stability of TNRC6A, a protein involved in RNA-mediated gene silencing by both micro-RNAs (miRNAs) and short interfering RNAs. This ubiquitination results in the suppressed expression of miR-138-5p leading to increased autophagy. Upon enteroviral infection, promotes 'Lys-63'-mediated ubiquitination activation of IFIH1/MDA5 leading to innate signaling cascade. Mechanistically, selectively recognizes MDA5 filaments that occur on dsRNAs.

1. Meng, J. et al. (2017) Cell death & disease 8, e2866. PMID: 28594402
2. Tang, T. et al. (2021) Frontiers in immunology 12, 741839. PMID: 34512673
3. Li, S. et al. (2014) Proceedings of the National Academy of Sciences of the United States of America 111, 6970-5. PMID: 24778252
4. Pan, X. et al. (2019) Cell death & disease 10, 429. PMID: 31160576
5. Kato, K. et al. (2021) Molecular cell 81, 599-613.e8. PMID: 33373584
6. Li, Y. et al. (2020) Journal of molecular cell biology 12, 190-201. PMID: 31310649
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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