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Anti-Human SLC38A3 Polyclonal Antibody (HC806014)

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概述
货号HC806014
品牌abinScience
描述
Anti-Human SLC38A3 Polyclonal Antibody (HC806014) is a rabbit polyclonal antibody detecting SLC38A3. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human SLC38A3 (Lys234-Asn323).
靶标G17, N-system amino acid transporter 1, NAT1, Na(+)-coupled neutral amino acid transporter 3, SLC38A3, SN1, SNAT3, Sodium-coupled neutral amino acid transporter 3, Solute carrier family 38 member 3, System N amino acid transporter 1
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q99624
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Sodium-coupled neutral amino acid transporter 3 (SLC38A3) is a ~55 kDa protein. Symporter that cotransports specific neutral amino acids and sodium ions, coupled to an H(+) antiporter activity. Mainly participates in the glutamate-GABA-glutamine cycle in brain where it transports L-glutamine from astrocytes in the intercellular space for the replenishment of both neurotransmitters glutamate and gamma-aminobutyric acid (GABA) in neurons and also functions as the major influx transporter in ganglion cells mediating the uptake of glutamine. The transport activity is specific for L-glutamine, L-histidine and L-asparagine. The transport is electroneutral coupled to the cotransport of 1 Na(+) and the antiport of 1 H(+). The transport is pH dependent, saturable, Li(+) tolerant and functions in both direction depending on the concentration gradients of its substrates and cotransported ions.

1. Fei, YJ. et al. (2000) The Journal of biological chemistry 275, 23707-17. PMID: 10823827
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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