首页 > 产品中心 > 抗体 > 一抗

Anti-Human DHX58 Polyclonal Antibody (HC201014)

价格:
规格:
  • 50ug
  • 100ug
数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号HC201014
品牌abinScience
描述
Anti-Human DHX58 Polyclonal Antibody (HC201014) is a rabbit polyclonal antibody detecting DHX58. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human DHX58 (Met1-Asp678).
靶标ATP-dependent RNA helicase DHX58, ATP-dependent helicase LGP2, D11LGP2E, DHX58, EC:3.6.4.13, LGP2, Protein D11Lgp2 homolog, RIG-I-like receptor 3, RIG-I-like receptor LGP2, RLR, RLR-3
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q96C10
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

ATP-dependent RNA helicase DHX58 is a ~76 kDa protein. Acts as a regulator of RIGI and IFIH1/MDA5 mediated antiviral signaling. Cannot initiate antiviral signaling as it lacks the CARD domain required for activating MAVS/IPS1-dependent signaling events. Can have both negative and positive regulatory functions related to RIGI and IFIH1/MDA5 signaling and this role in regulating signaling may be complex and could probably depend on characteristics of the infecting virus or target cells, or both. Its inhibitory action on RIG-I signaling may involve the following mechanisms: competition with RIGI for binding to the viral RNA, binding to RIGI and inhibiting its dimerization and interaction with MAVS/IPS1, competing with IKBKE in its binding to MAVS/IPS1 thereby inhibiting activation of interferon regulatory factor 3 (IRF3). Its positive regulatory role may involve unwinding or stripping nucleoproteins of viral RNA thereby facilitating their recognition by RIGI and IFIH1/MDA5.

1. Paine, I. et al. (2019) American journal of human genetics 105, 302-316. PMID: 31256877
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

相关产品推荐