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Anti-BCAT2 Polyclonal Antibody (HT209014)

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概述
货号HT209014
品牌abinScience
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human BCAT2 (Ala107-Val392).
靶标BCT2, BCAT2, BCAT(m), BCATM, Placental protein 18, Branched-chain-amino-acid aminotransferase, mitochondrial, PP18, ECA40
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号O15382
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Branched-chain-amino-acid aminotransferase, mitochondrial (BCAT2) is a ~44 kDa protein. Catalyzes the first reaction in the catabolism of the essential branched chain amino acids leucine, isoleucine, and valine. Branched chain amino acid catabolism plays a role in adipocyte differentiation by providing lipogenic acetyl-CoA pools in differentiated adipocytes. Mechanistically, acetyl-CoA derived from branched chain amino acid catabolism is used by EP300/p300 to acetylate and inhibit PRDM16, thereby preventing adipose tissue browning. May also function as a transporter of branched chain alpha-keto acids.

1. Yennawar, NH. et al. (2006) The Journal of biological chemistry 281, 39660-71. PMID: 17050531
2. Wang, XL. et al. (2015) Journal of inherited metabolic disease 38, 855-61. PMID: 25653144
3. Eden, A. et al. (1996) The Journal of biological chemistry 271, 20242-5. PMID: 8702755
文献1. Lei Zhao, et al. Design, screening and biological evaluation of novel fatty acid chain-modified oxyntomodulin-based derivatives with prolonged glucose-lowering ability and potent anti-obesity effects. Org Biomol Chem. 2019, 17, 33. [HT209014]
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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