首页 > 产品中心 > 抗体 > 一抗

Anti-GLUD1 Polyclonal Antibody (HF014014)

价格:
规格:
  • 50ug
  • 100ug
数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号HF014014
品牌abinScience
描述
Anti-GLUD1 Polyclonal Antibody (HF014014) is a rabbit polyclonal antibody detecting GLUD1 in ELISA, IHC, WB. Suitable for Human, Mouse, Bovine, Chicken, and Hylobates lar.
Highlights
  • Affinity Purified — Minimal background and high purity for reliable results.
  • Multi-Application — Validated across multiple applications.
  • Multi-Species — Cross-reactive for translational research.
种属反应性Human, Mouse, Rat
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Human GLUD1 (Asp334-Thr556).
靶标GLUD1, GDH 1, Glutamate dehydrogenase 1, mitochondrial, GLUD
纯化方式Purified by antigen affinity column.
Accession号P00367
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Glutamate dehydrogenase 1, mitochondrial (GLUD1) is a ~61 kDa protein. Mitochondrial glutamate dehydrogenase that catalyzes the conversion of L-glutamate into alpha-ketoglutarate. Plays a key role in glutamine anaplerosis by producing alpha-ketoglutarate, an important intermediate in the tricarboxylic acid cycle. Plays a role in insulin homeostasis. May be involved in learning and memory reactions by increasing the turnover of the excitatory neurotransmitter glutamate.

1. Plaitakis, A. et al. (2000) Journal of neurochemistry 75, 1862-9. PMID: 11032875
2. Smith, TJ. et al. (2001) Journal of molecular biology 307, 707-20. PMID: 11254391
3. Choi, MM. et al. (2005) FEBS letters 579, 4125-30. PMID: 16023112
4. Haigis, MC. et al. (2006) Cell 126, 941-54. PMID: 16959573
5. MacMullen, C. et al. (2001) The Journal of clinical endocrinology and metabolism 86, 1782-7. PMID: 11297618
6. Stanley, CA. et al. (1998) The New England journal of medicine 338, 1352-7. PMID: 9571255
NoteFor research use only.
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

相关产品推荐