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Anti-Corynephage omega DT/Diphtheria toxin Reference Antibody (DTD4, RUO) (JN967016)

价格:
规格:
  • 100ug
  • 1mg
  • 5mg
  • 10mg
  • 25mg
  • 50mg
  • 100mg
数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号JN967016
品牌abinScience
描述
Anti-Corynephage omega DT/Diphtheria toxin Antibody (DTD4) (JN967016) is a research-grade recombinant antibody targeting Diphtheria toxin. Produced in mammalian cells with native-like glycosylation.
Highlights
  • Research Grade — For PK/PD studies, assay development, and ADA research.
  • Native Glycosylation — Mammalian expression ensures native-like patterns.
种属反应性Corynephage omega
应用ELISA, Bioactivity: FACS, Functional assay, Research in vivo
同种型IgG2-kappa
克隆号DTD4
表达系统Mammalian cells
靶标Diphtheria toxin, DT, NAD(+)--diphthamide ADP-ribosyltransferase, 2.4.2.36, Diphtheria toxin fragment A, Diphtheria toxin fragment B
内毒素水平< 10 EU/mg
纯度>95% purity as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号P00587
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Diphtheria toxin (DT) is a ~60 kDa protein. Diphtheria toxin, produced by a phage infecting Corynebacterium diphtheriae, is a proenzyme that, after activation, catalyzes the covalent attachment of the ADP ribose moiety of NAD to elongation factor 2. Fragment A is responsible for enzymatic ADP-ribosylation of elongation factor 2, while fragment B is responsible for binding of toxin to cell receptors and entry of fragment A.

NoteFor research use only. Not suitable for clinical or therapeutic use.
Isotype ControlHuman IgG2 Recombinant Isotype Control Antibody (HyHEL-10) (HV988107)
图片
  • SDS-PAGE

    SDS-PAGE for Research Grade Anti-Corynephage omega DT/Diphtheria toxin Antibody (DTD4).

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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