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Anti-Human CD83 Reference Antibody (CBT004, RUO) (HX237016)

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规格:
  • 100ug
  • 1mg
  • 5mg
  • 10mg
  • 25mg
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数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号HX237016
品牌abinScience
描述
Anti-Human CD83 (CBT004) (HX237016) is a research-grade recombinant antibody targeting CD83. Produced in mammalian cells with native-like glycosylation.
Highlights
  • Research Grade — For PK/PD studies, assay development, and ADA research.
  • Native Glycosylation — Mammalian expression ensures native-like patterns.
种属反应性Human
应用ELISA, Bioactivity: FACS, Functional assay, Research in vivo
宿主Human
同种型IgG
克隆号CBT004
表达系统Mammalian cells
克隆类型Monoclonal
靶标CD83, hCD83, CD83 antigen, B-cell activation protein, Cell surface protein HB15
内毒素水平< 10 EU/mg
纯度>95% purity as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号Q01151
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名CBT004
背景

CD83 antigen is a ~23 kDa protein. Transmembrane glycoprotein predominantly found on the surface of many immune cells including dendritic cells or lymphocytes that plays various roles in immune response regulation. Plays an essential role in CD4(+) T-selection, differentiation and stability by regulating the activity of the major E3 ubiquitin ligase responsible for controlling MHCII trafficking MARCHF8. Also inhibits MARCHF1 association with MHCII or CD86 to prevent their ubiquitination and subsequent degradation. In addition, acts as an important modulator of protective responses against acute infections.

1. Tze, LE. et al. (2011) The Journal of experimental medicine 208, 149-65. PMID: 21220452
NoteFor research use only. Not suitable for clinical or therapeutic use.
图片
  • SDS-PAGE

    SDS-PAGE for Research Grade Anti-Human CD83 (CBT004)

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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