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Human ZNF93 Recombinant Protein (N-His) (HD019012)

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概述
货号HD019012
品牌abinScience
描述
Recombinant Human ZNF93 Protein, N-His (HD019012) expressed in E. coli, spanning Phe145-Pro620. Purity: >90% by SDS-PAGE.
Highlights
  • ●His-Tagged — N-terminal 6×His tag for IMAC purification.
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% purity verified by SDS-PAGE.
表达系统E. coli
Accession号P35789
蛋白长度Phe145-Pro620
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Homo sapiens (Human)
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
预测分子量56.68 kDa
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名ZNF505, ZNF93, Zinc finger protein 505, Zinc finger protein 93, Zinc finger protein HTF34
背景

Zinc finger protein 93 is a ~70 kDa protein. Transcription factor specifically required to repress long interspersed nuclear element 1 (L1) retrotransposons: recognizes and binds L1 sequences and repress their expression by recruiting a repressive complex containing TRIM28/KAP1. Not able to repress expression of all subtypes of L1 elements. Binds to the 5' end of L1PA4, L1PA5 and L1PA6 subtypes, and some L1PA3 subtypes. Does not bind to L1PA7 or older subtypes nor at the most recently evolved L1PA2 and L1Hs. 50% of L1PA3 elements have lost the ZNF93-binding site, explaining why ZNF93 is not able to repress their expression.

1. Jacobs, FM. et al. (2014) Nature 516, 242-5. PMID: 25274305
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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