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Human UBE4B Recombinant Protein (N-His) (HD151012)

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概述
货号HD151012
品牌abinScience
描述
Recombinant Human UBE4B Protein, N-His (HD151012) expressed in E. coli, spanning Leu961-His1302. Purity: >90% by SDS-PAGE.
Highlights
  • ●His-Tagged — N-terminal 6×His tag for IMAC purification.
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% purity verified by SDS-PAGE.
表达系统E. coli
Accession号O95155
蛋白长度Leu961-His1302
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Homo sapiens (Human)
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
预测分子量42.23 kDa
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名EC:2.3.2.27, HDNB1, Homozygously deleted in neuroblastoma 1, KIAA0684, RING-type E3 ubiquitin transferase E4 B, UBE4B, UFD2, Ubiquitin conjugation factor E4 B, Ubiquitin fusion degradation protein 2
背景

Ubiquitin conjugation factor E4 B is a ~146 kDa protein. Ubiquitin-protein ligase that probably functions as an E3 ligase in conjunction with specific E1 and E2 ligases. May also function as an E4 ligase mediating the assembly of polyubiquitin chains on substrates ubiquitinated by another E3 ubiquitin ligase. May regulate myosin assembly in striated muscles together with STUB1 and VCP/p97 by targeting myosin chaperone UNC45B for proteasomal degradation.

1. Janiesch, PC. et al. (2007) Nature cell biology 9, 379-90. PMID: 17369820
NoteFor research use only
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参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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