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Human NAA30 Recombinant Protein (N-His) (HD223012)

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  • 1mg
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概述
货号HD223012
品牌abinScience
描述
Recombinant Human NAA30 Protein, N-His (HD223012) expressed in E. coli, spanning Gln79-Arg362. Purity: >90% by SDS-PAGE.
Highlights
  • ●His-Tagged — N-terminal 6×His tag for IMAC purification.
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% purity verified by SDS-PAGE.
表达系统E. coli
Accession号Q147X3
蛋白长度Gln79-Arg362
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Homo sapiens (Human)
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
预测分子量33.91 kDa
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名C14orf35, EC:2.3.1.256, MAK3, N-acetyltransferase 12, N-acetyltransferase MAK3 homolog, N-alpha-acetyltransferase 30, NAA30, NAT12, NatC catalytic subunit
背景

N-alpha-acetyltransferase 30 is a ~39 kDa protein. Catalytic subunit of the N-terminal acetyltransferase C (NatC) complex. Catalyzes acetylation of the N-terminal methionine residues of peptides beginning with Met-Leu-Ala and Met-Leu-Gly. N-terminal acetylation protects proteins from ubiquitination and degradation by the N-end rule pathway. Necessary for the lysosomal localization and function of ARL8B sugeesting that ARL8B is a NatC substrate.

1. Starheim, KK. et al. (2009) Molecular and cellular biology 29, 3569-81. PMID: 19398576
2. Varland, S. et al. (2023) Nature communications 14, 6774. PMID: 37891180
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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