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Aspergillus flavus Uricase Recombinant Protein (N-His) (JA150012)

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概述
货号JA150012
品牌abinScience
描述
Recombinant Aspergillus flavus Uricase Protein, N-His (JA150012) expressed in E. coli. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% as determined by SDS-PAGE.
表达系统E. coli
Accession号Q00511
蛋白长度Met1-Leu302
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Aspergillus flavus
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.
重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名EC:1.7.3.3, Rasburicase, Uox, Urate oxidase, Uricase, uaZ
背景

Uricase is a ~34 kDa protein. Urate oxidase is a cofactorless enzyme involved in the metabolism of purines (PubMed:1339455, PubMed:17020862, PubMed:28272834, Ref.3). Catalyzes, in the presence of molecular oxygen, the hydroxylation of uric acid to metastable 5-hydroxyisourate (5-HIU) which is further degraded to allantoin.

1. Legoux, R. et al. (1992) The Journal of biological chemistry 267, 8565-70. PMID: 1339455
2. Bayol, A. et al. (1995) Biophysical chemistry 54, 229-35. PMID: 17020862
3. Cheuk, DK. et al. (2017) The Cochrane database of systematic reviews 3, CD006945. PMID: 28272834
NoteFor research use only
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产品说明书
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量，自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项，自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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