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Human PPP1R11 Recombinant Protein (N-His-KSI) (HD625012)

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规格:
  • 50ug
  • 100ug
  • 1mg
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概述
货号HD625012
品牌abinScience
描述
Recombinant Human PPP1R11 Protein, N-His-KSI (HD625012) expressed in E. coli. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% as determined by SDS-PAGE.
表达系统E. coli
Accession号O60927
蛋白长度Arg26-His126
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Homo sapiens (Human)
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名E3 ubiquitin-protein ligase PPP1R11, EC:2.3.2.27, HCG V, HCGV, Hemochromatosis candidate gene V protein, PPP1R11, Protein phosphatase 1 regulatory subunit 11, Protein phosphatase inhibitor 3, TCTE5
背景

E3 ubiquitin-protein ligase PPP1R11 is a ~13 kDa protein. Atypical E3 ubiquitin-protein ligase which ubiquitinates TLR2 at 'Lys-754' leading to its degradation by the proteasome. Plays a role in regulating inflammatory cytokine release and gram-positive bacterial clearance by functioning, in part, through the ubiquitination and degradation of TLR2. Inhibitor of protein phosphatase 1.

1. McKelvey, AC. et al. (2016) eLife 5. PMID: 27805901
2. Zhang, J. et al. (1998) Biochemistry 37, 16728-34. PMID: 9843442
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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