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Bacillus cereus gajB Recombinant Protein (N-His) (JN922022)

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  • 50ug
  • 100ug
  • 1mg
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概述
货号JN922022
品牌abinScience
描述
Recombinant Bacillus cereus gajB Protein, N-His (JN922022) expressed in E. coli. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% as determined by SDS-PAGE.
表达系统E. coli
Accession号J8HQ06
蛋白长度Met1-Ile494
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Bacillus cereus
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
预测分子量59.23 kDa
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名Gabija protein GajB, Putative helicase GajB, gajB
背景

Gabija protein GajB is a ~57 kDa protein. Component of antiviral defense system Gabija type I, composed of GajA and GajB. Expression of Gabija type I in B.subtilis (strain BEST7003) confers resistance to phages phi105, phi29, rho14, SpBeta and SBSphiC. Expression of Gabija type I in E.coli B (strain ATCC 11303) confers resistance to phage T7. May be a helicase or contribute to GajA activation (Probable).

1. Doron, S. et al. (2018) Science (New York, N.Y.) 359. PMID: 29371424
2. Cheng, R. et al. (2021) Nucleic acids research 49, 5216-5229. PMID: 33885789
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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