首页 > 产品中心 > 重组蛋白 > 其他蛋白

Human ERCC6 Recombinant Protein (N-His) (HD786012)

价格: --
规格:
  • 50ug
  • 100ug
  • 1mg
数量:
  • 概述

  • 图片

  • 参考文献

  • 产品说明书

概述
货号HD786012
品牌abinScience
描述
Recombinant Human ERCC6 Protein, N-His (HD786012) expressed in E. coli. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% as determined by SDS-PAGE.
表达系统E. coli
Accession号P0DP91
蛋白长度Val606-Gly996
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Homo sapiens (Human)
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
预测分子量47.60 kDa
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名Chimeric CSB-PGBD3 protein, Chimeric ERCC6-PGBD3 protein, ERCC6
背景

Chimeric ERCC6-PGBD3 protein is a ~119 kDa protein. Involved in repair of DNA damage following UV irradiation, acting either in the absence of ERCC6 or synergistically with ERCC6. Involved in the regulation of gene expression. In the absence of ERCC6, induces the expression of genes characteristic of interferon-like antiviral responses. This response is almost completely suppressed in the presence of ERCC6. In the presence of ERCC6, regulates the expression of genes involved in metabolism regulation, including IGFBP5 and IGFBP7.

NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

相关产品推荐