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Human SLC25A27 Recombinant Protein (N-GST & C-His) (HD822012)

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规格:
  • 50ug
  • 100ug
  • 1mg
数量:
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概述
货号HD822012
品牌abinScience
描述
Recombinant Human SLC25A27 Protein, N-GST & C-His (HD822012) expressed in E. coli. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●E. coli Expression — High-yield, cost-effective production.
  • ●High Purity — >90% as determined by SDS-PAGE.
表达系统E. coli
Accession号O95847
蛋白长度Leu40-Trp88&Leu144-Phe195248
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Homo sapiens (Human)
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
预测分子量53.89 kDa
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名Mitochondrial uncoupling protein 4, SLC25A27, Solute carrier family 25 member 27, UCP 4, UCP4
背景

Mitochondrial uncoupling protein 4 is a ~36 kDa protein. Facilitates proton transport across the inner mitochondrial membrane and may dissipate excessive proton gradient associated with oxidative and metabolic stress at neuronal synapses. Regulates glutamate-induced proton conductance in astrocytes, shifting the energy metabolism toward aerobic glycolysis and lactate transfer to neurons for ATP synthesis. Can transport chloride ions with lower efficiency. The transport mechanism remains to be elucidated.

NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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