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Anti-Clostridium botulinum BoNT/E Recombinant Antibody (SAA2610) (JN161013)

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  • 100ug
  • 1mg
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概述
货号JN161013
品牌abinScience
种属反应性Clostridium botulinum
应用ELISA
宿主Mouse
克隆类型Monoclonal
同种型IgG
克隆号SAA2610
靶标BoNT/E, Bontoxilysin-E, Botulinum neurotoxin E heavy chain, Botulinum neurotoxin E light chain, Botulinum neurotoxin type E, EC:3.4.24.69, HC, LC, botE
内毒素水平Please contact with the lab for this information.
纯度>95% as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号Q00496
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:2000-1:20000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Botulinum neurotoxin type E (BoNT) is a ~143 kDa protein. Botulinum toxin causes flaccid paralysis by inhibiting neurotransmitter (acetylcholine) release from the presynaptic membranes of nerve terminals of eukaryotic host skeletal and autonomic nervous system, with frequent heart or respiratory failure. Precursor of botulinum neurotoxin E which has 2 coreceptors; complex polysialylated gangliosides found on neural tissue and specific membrane-anchored proteins found in synaptic vesicles. Receptor proteins are exposed on host presynaptic cell membrane during neurotransmitter release, when the toxin heavy chain (HC) binds to them. Upon synaptic vesicle recycling the toxin is taken up via the endocytic pathway. When the pH of the toxin-containing endosome drops a structural rearrangement occurs so that the N-terminus of the HC forms pores that allows the light chain (LC) to translocate into the cytosol.

1. Fu, Z. et al. (2009) Biochemistry 48, 5631-41. PMID: 19476346
2. Rummel, A. et al. (2009) Journal of neurochemistry 110, 1942-54. PMID: 19650874
3. Sun, S. et al. (2012) Biochemistry 51, 5655-62. PMID: 22720883
4. Dong, M. et al. (2008) Molecular biology of the cell 19, 5226-37. PMID: 18815274
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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