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Anti-Escherichia coli eae/Intimin Polyclonal Antibody (JN084014)

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规格:
  • 50ug
  • 100ug
数量:
  • 概述

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  • 参考文献

  • 产品说明书

概述
货号JN084014
品牌abinScience
种属反应性Escherichia coli
应用ELISA, IHC, WB
宿主Rabbit
同种型IgG
克隆类型Polyclonal
免疫原E. coli - derived recombinant Escherichia coli eae/Intimin (Lys450-Gln655).
靶标Intimin, Attaching and effacing protein, Eae protein, eae, eaeA, E2348C_3939
纯化方式Purified by antigen affinity column.
Accession号P19809
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
背景

Intimin (eae) is a ~102 kDa protein. An inverse autotransporter. Adhesin, which mediates attachment to the human intestine epithelial cells. Necessary for the production of attaching and effacing lesions on infected human tissue culture cells. Anchored to the outer membrane by binding to peptidoglycan (PGN) via its periplasmic domain, thus helping in receptor interactions during host invasion (Probable). PGN-binding may also aid in resisting mechanical and chemical stress during transit of the bacterium through the gastrointestinal tract of the host (Probable).

1. Leo, JC. et al. (2015) Molecular microbiology 95, 80-100. PMID: 25353290
2. Weikum, J. et al. (2020) Scientific reports 10, 21249. PMID: 33277518
3. Jerse, AE. et al. (1990) Proceedings of the National Academy of Sciences of the United States of America 87, 7839-43. PMID: 2172966
4. Batchelor, M. et al. (2000) The EMBO journal 19, 2452-64. PMID: 10835344
NoteFor research use only.
图片
  • Western blot

    Western blot analysis was performed using anti-EAE polyclonal antibody at 1ug/mL on various samples.
    Lane 1: recombinant Escherichia coli eae/Intimin (Catalog No: JN084012)

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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