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Anti-Human IL19 Recombinant Antibody (SAA1626) (HV492013)

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规格:
  • 50ug
  • 100ug
  • 1mg
数量:
  • 概述

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  • 参考文献

  • 产品说明书

概述
货号HV492013
品牌abinScience
种属反应性Human
应用ELISA
同种型IgG2a, kappa
克隆号SAA1626
靶标Melanoma differentiation-associated protein-like protein, Interleukin-19, IL-19, IL19, NG.1, ZMDA1
内毒素水平Please contact with the lab for this information.
纯度>95% as determined by SDS-PAGE.
纯化方式Protein A/G purified from cell culture supernatant.
Accession号Q9UHD0
RRIDAnti-Human IL19 Antibody (SAA1626) (abinScience Cat# HV492013, RRID:AB_3727387)
状态Liquid
保存溶液 0.01M PBS pH 7.4

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:2000-1:20000
稳定性和存储Use a manual defrost freezer and avoid repeated freeze-thaw cycles. Store at 4°C short term (1-2 weeks). Store at -20°C 12 months. Store at -80°C long term.
背景

Interleukin-19 (IL19) is a ~20 kDa protein. Cytokine that functions as an anti-inflammatory and proangiogenic factor. Polarizes adaptive immunity to an anti-inflammatory phenotype through induction of T-helper 2 responses by both down-regulation of IFN-gamma and up-regulation of IL4 and IL13. Produced by osteocytes, stimulates granulopoiesis and neutrophil formation. Exerts its biological effect through a receptor complex consisting of a heterodimer of IL20RA and IL20RB. In turn, activates the Janus kinase (JAK) and signal transducer and activator of transcription (STAT) pathway, and importantly, STAT3.

1. Small, SH. et al. (2021) Science signaling 14, eaba2611. PMID: 34932373
2. Oral, HB. et al. (2006) European journal of immunology 36, 380-8. PMID: 16365913
3. Parrish-Novak, J. et al. (2002) The Journal of biological chemistry 277, 47517-23. PMID: 12351624
4. Dumoutier, L. et al. (2001) Journal of immunology (Baltimore, Md. : 1950) 167, 3545-9. PMID: 11564763
NoteFor research use only.
图片
  • SDS-PAGE

    SDS-PAGE for Anti-Human IL19 Antibody (SAA1626)

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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