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Anti-Human CDT1 Polyclonal Antibody (HD509014)

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  • 100ug
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  • 参考文献

  • 产品说明书

概述
货号HD509014
品牌abinScience
描述
Anti-Human CDT1 Polyclonal Antibody (HD509014) is a rabbit polyclonal antibody detecting CDT1. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human CDT1 (Thr112-Ser386).
靶标CDT1, DNA replication factor Cdt1, DUP, Double parked homolog
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q9H211
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

DNA replication factor Cdt1 is a ~60 kDa protein. Required for both DNA replication and mitosis. DNA replication licensing factor, required for pre-replication complex assembly. Cooperates with CDC6 and the origin recognition complex (ORC) during G1 phase of the cell cycle to promote the loading of the mini-chromosome maintenance (MCM) complex onto DNA to generate pre-replication complexes (pre-RC). Required also for mitosis by promoting stable kinetochore-microtubule attachments. Potential oncogene.

1. Wohlschlegel, JA. et al. (2000) Science (New York, N.Y.) 290, 2309-12. PMID: 11125146
2. Sugimoto, N. et al. (2004) The Journal of biological chemistry 279, 19691-7. PMID: 14993212
3. Miotto, B. et al. (2011) Molecular cell 44, 62-71. PMID: 21856198
4. Varma, D. et al. (2012) Nature cell biology 14, 593-603. PMID: 22581055
5. Franz, A. et al. (2016) Nature communications 7, 10612. PMID: 26842564
6. Cook, JG. et al. (2004) The Journal of biological chemistry 279, 9625-33. PMID: 14672932
NoteFor research use only
图片
  • Western blot

    Lane 1: HCT116 cell lysate
    Lane 2: Jurkat cell lysate
    Lane 3: K562 cell lysate
    Lane 4: MCF-7 cell lysate
    Lane 5: Hela cell lysate

参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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