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Anti-Human FAAH Polyclonal Antibody (HD694014)

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概述
货号HD694014
品牌abinScience
描述
Anti-Human FAAH Polyclonal Antibody (HD694014) is a rabbit polyclonal antibody detecting FAAH. Suitable for Human.
种属反应性Human
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human FAAH (Ser71-Ser579).
靶标Anandamide amidohydrolase 1, EC:3.1.1.-, EC:3.5.1.99, FAAH, FAAH1, Fatty acid ester hydrolase, Fatty-acid amide hydrolase 1, Oleamide hydrolase 1
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号O00519
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Fatty-acid amide hydrolase 1 (FAAH) is a ~63 kDa protein. Catalyzes the hydrolysis of endogenous amidated lipids like the sleep-inducing lipid oleamide ((9Z)-octadecenamide), the endocannabinoid anandamide (N-(5Z,8Z,11Z,14Z-eicosatetraenoyl)-ethanolamine), as well as other fatty amides, to their corresponding fatty acids, thereby regulating the signaling functions of these molecules. Hydrolyzes polyunsaturated substrate anandamide preferentially as compared to monounsaturated substrates. It can also catalyze the hydrolysis of the endocannabinoid 2-arachidonoylglycerol (2-(5Z,8Z,11Z,14Z-eicosatetraenoyl)-glycerol). FAAH cooperates with PM20D1 in the hydrolysis of amino acid-conjugated fatty acids such as N-fatty acyl glycine and N-fatty acyl-L-serine, thereby acting as a physiological regulator of specific subsets of intracellular, but not of extracellular, N-fatty acyl amino acids.

1. Wei, BQ. et al. (2006) The Journal of biological chemistry 281, 36569-78. PMID: 17015445
2. Kaczocha, M. et al. (2010) The Journal of biological chemistry 285, 2796-806. PMID: 19926788
3. Giang, DK. et al. (1997) Proceedings of the National Academy of Sciences of the United States of America 94, 2238-42. PMID: 9122178
4. Xie, S. et al. (2010) Chemical research in toxicology 23, 1890-904. PMID: 21049984
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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