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Anti-Human LUZP1 Polyclonal Antibody (HC252014)

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概述
货号HC252014
品牌abinScience
描述
Anti-Human LUZP1 Polyclonal Antibody (HC252014) is a rabbit polyclonal antibody detecting LUZP1. Suitable for Human and Rat.
Highlights
  • ●Multi-Species — Cross-reactive for translational research.
种属反应性Human, Rat
应用ELISA, IHC, WB
宿主Rabbit
克隆类型Polyclonal
同种型IgG
免疫原E. coli - derived recombinant Human LUZP1 (Met157-Gln350).
靶标Filamin mechanobinding actin cross-linking protein, Fimbacin, LUZP1, Leucine zipper protein 1
内毒素水平Please contact with the lab for this information.
纯化方式Purified by antigen affinity column.
Accession号Q86V48
状态Liquid
保存溶液 0.01M PBS, pH 7.4, 50% Glycerol, 0.05% Proclin 300.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.

产品使用信息
应用方法 稀释比例
ELISA 1:5000-1:20000
IHC 1:50-1:500
WB 1:500-1:2000
背景

Leucine zipper protein 1 (LUZP1) is a ~120 kDa protein. F-actin cross-linking protein. Stabilizes actin and acts as a negative regulator of primary cilium formation. Positively regulates the phosphorylation of both myosin II and protein phosphatase 1 regulatory subunit PPP1R12A/MYPT1 and promotes the assembly of myosin II stacks within actin stress fibers. Inhibits the phosphorylation of myosin light chain MYL9 by DAPK3 and suppresses the constriction velocity of the contractile ring during cytokinesis. Binds to microtubules and promotes epithelial cell apical constriction by up-regulating levels of diphosphorylated myosin light chain (MLC) through microtubule-dependent inhibition of MLC dephosphorylation by myosin phosphatase.

1. Wang, J. et al. (2019) Biochemistry 58, 4737-4743. PMID: 30990684
2. Gonçalves, J. et al. (2020) The Journal of cell biology 219. PMID: 32496561
3. Wang, L. et al. (2024) Cellular and molecular life sciences : CMLS 81, 248. PMID: 38832964
4. Hyodo, T. et al. (2024) The FEBS journal 291, 927-944. PMID: 38009294
NoteFor research use only
图片
参考文献
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量,自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项,自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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