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Mycobacterium tuberculosis Isocitrate lyase/ICL Recombinant Protein (C-Strep) (JN930022)

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  • 1mg
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概述
货号JN930022
品牌abinScience
描述
Recombinant Mycobacterium tuberculosis Isocitrate lyase/ICL Protein, C-Strep (JN930022) expressed in B. subtilis. Purity: >90% as determined by SDS-PAGE..
Highlights
  • ●High Purity — >90% as determined by SDS-PAGE.
表达系统B. subtilis
Accession号P9WKK7
蛋白长度Met1-His428
应用ELISA, Immunogen, SDS-PAGE, WB, Bioactivity testing in progress
种属Mycobacterium tuberculosis
性质Recombinant
内毒素水平Please contact with the lab for this information.
纯度>90% as determined by SDS-PAGE.
状态Lyophilized
保存溶液 Lyophilized from a solution in PBS pH 7.4, 1 mM EDTA, 4% Trehalose, 1% Mannitol.

Please refer to the specific buffer information in the hardcopy of datasheet or the lot-specific COA.
重悬Reconstitute in sterile water for a stock solution. A copy of datasheet will be provided with the products, please refer to it for details.
运输In general, proteins are provided as lyophilized powder/frozen liquid. They are shipped out with dry ice/blue ice unless customers require otherwise.
稳定性和存储Use a manual defrost freezer and avoid repeated freeze thaw cycles. Store at 2 to 8°C for frequent use. Store at -20 to -80°C for twelve months from the date of receipt.
别名EC:4.1.3.1, ICL, Isocitrase, Isocitratase, Isocitrate lyase, icl
背景

Isocitrate lyase is a ~47 kDa protein. Involved in the persistence and virulence of M.tuberculosis. Catalyzes the reversible formation of succinate and glyoxylate from isocitrate, a key step of the glyoxylate cycle, which operates as an anaplerotic route for replenishing the tricarboxylic acid cycle during growth on fatty acid substrates. It could also catalyze the formation of pyruvate and succinate from 2-methylisocitrate, a key step in the methylcitrate cycle (propionate degradation route).

1. Sharma, V. et al. (2000) Nature structural biology 7, 663-8. PMID: 10932251
2. McKinney, JD. et al. (2000) Nature 406, 735-8. PMID: 10963599
3. Kumar, R. et al. (2008) Proteins 72, 892-900. PMID: 18275086
4. Moynihan, MM. et al. (2014) Biochemistry 53, 178-87. PMID: 24354272
NoteFor research use only
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参考文献
产品说明书
公式
质量 (g) = 浓度 (mol/L) × 体积 (L) × 分子量 (g/mol)
填写 质量、浓度、体积中的任意 2 项 + 分子量，自动计算未知值。
质量
=
浓度
×
体积
分子量 *
g/mol
公式
C₁ × V₁ = C₂ × V₂
填写 4 项中的任意 3 项，自动计算未知值。
母液
C₁ (起始浓度)
×
V₁ (起始体积)
=
工作液
C₂ (终浓度)
×
V₂ (终体积)

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